8-4(y-1)=2+3(4-y)

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Solution for 8-4(y-1)=2+3(4-y) equation: 



8-4(y-1)=2+3(4-y)

We move all terms to the left:

8-4(y-1)-(2+3(4-y))=0

We add all the numbers together, and all the variables

-4(y-1)-(2+3(-1y+4))+8=0

We multiply parentheses

-4y-(2+3(-1y+4))+4+8=0



We calculate terms in parentheses: -(2+3(-1y+4)), so:

2+3(-1y+4)

determiningTheFunctionDomain
3(-1y+4)+2

We multiply parentheses

-3y+12+2

We add all the numbers together, and all the variables

-3y+14

Back to the equation:

-(-3y+14)



We add all the numbers together, and all the variables

-4y-(-3y+14)+12=0

We get rid of parentheses

-4y+3y-14+12=0

We add all the numbers together, and all the variables

-1y-2=0

We move all terms containing y to the left, all other terms to the right

-y=2

y=2/-1

y=-2

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