6(2x-4)=8(x-2)

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Solution for 6(2x-4)=8(x-2) equation: 



6(2x-4)=8(x-2)

We move all terms to the left:

6(2x-4)-(8(x-2))=0

We multiply parentheses

12x-(8(x-2))-24=0



We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

12x-8x+16-24=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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