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(x+12)+(x-3)=(5x-6)
We move all terms to the left:
(x+12)+(x-3)-((5x-6))=0
We get rid of parentheses
x+x-((5x-6))+12-3=0
We calculate terms in parentheses: -((5x-6)), so:We add all the numbers together, and all the variables
(5x-6)
We get rid of parentheses
5x-6
Back to the equation:
-(5x-6)
2x-(5x-6)+9=0
We get rid of parentheses
2x-5x+6+9=0
We add all the numbers together, and all the variables
-3x+15=0
We move all terms containing x to the left, all other terms to the right
-3x=-15
x=-15/-3
x=+5
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