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6(2x-3)=12(x-1)
We move all terms to the left:
6(2x-3)-(12(x-1))=0
We multiply parentheses
12x-(12(x-1))-18=0
We calculate terms in parentheses: -(12(x-1)), so:We get rid of parentheses
12(x-1)
We multiply parentheses
12x-12
Back to the equation:
-(12x-12)
12x-12x+12-18=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation
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