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3(x-1)-(4x-5)=2(5x+1)-7
We move all terms to the left:
3(x-1)-(4x-5)-(2(5x+1)-7)=0
We multiply parentheses
3x-(4x-5)-(2(5x+1)-7)-3=0
We get rid of parentheses
3x-4x-(2(5x+1)-7)+5-3=0
We calculate terms in parentheses: -(2(5x+1)-7), so:We add all the numbers together, and all the variables
2(5x+1)-7
We multiply parentheses
10x+2-7
We add all the numbers together, and all the variables
10x-5
Back to the equation:
-(10x-5)
-1x-(10x-5)+2=0
We get rid of parentheses
-1x-10x+5+2=0
We add all the numbers together, and all the variables
-11x+7=0
We move all terms containing x to the left, all other terms to the right
-11x=-7
x=-7/-11
x=7/11
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