6(2x-3)+10=16

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Solution for 6(2x-3)+10=16 equation: 



6(2x-3)+10=16

We move all terms to the left:

6(2x-3)+10-(16)=0

We add all the numbers together, and all the variables

6(2x-3)-6=0

We multiply parentheses

12x-18-6=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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