6x+4-x2(x+1)10=2(x+1)

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Solution for 6x+4-x2(x+1)10=2(x+1) equation: 



6x+4-x2(x+1)10=2(x+1)

We move all terms to the left:

6x+4-x2(x+1)10-(2(x+1))=0

We multiply parentheses

-10x^3-10x^2+6x-(2(x+1))+4=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We do not support expression: x^3

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