6(2x-1)+7=1/2(4x-2)

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Solution for 6(2x-1)+7=1/2(4x-2) equation: 



6(2x-1)+7=1/2(4x-2)

We move all terms to the left:

6(2x-1)+7-(1/2(4x-2))=0



Domain of the equation: 2(4x-2))!=0

x∈R



We multiply parentheses

12x-(1/2(4x-2))-6+7=0

We multiply all the terms by the denominator


12x*2(4x-2))-(1-6*2(4x-2))+7*2(4x-2))=0

We add all the numbers together, and all the variables

12x*2(4x-2))-(1-6*2(4x-2))+7*2(4x=0

Wy multiply elements

24x^2(4-24x^2(4=0

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