(12x+3)+(9x-6)=18

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Solution for (12x+3)+(9x-6)=18 equation: 



(12x+3)+(9x-6)=18

We move all terms to the left:

(12x+3)+(9x-6)-(18)=0

We get rid of parentheses

12x+9x+3-6-18=0

We add all the numbers together, and all the variables

21x-21=0

We move all terms containing x to the left, all other terms to the right

21x=21

x=21/21

x=1

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