6(2x+3)=42+4x

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Solution for 6(2x+3)=42+4x equation: 



6(2x+3)=42+4x

We move all terms to the left:

6(2x+3)-(42+4x)=0

We add all the numbers together, and all the variables

6(2x+3)-(4x+42)=0

We multiply parentheses

12x-(4x+42)+18=0

We get rid of parentheses

12x-4x-42+18=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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