-2b+5b=-(1+3b)+7(b-1)

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Solution for -2b+5b=-(1+3b)+7(b-1) equation: 



-2b+5b=-(1+3b)+7(b-1)

We move all terms to the left:

-2b+5b-(-(1+3b)+7(b-1))=0

We add all the numbers together, and all the variables

-2b+5b-(-(3b+1)+7(b-1))=0

We add all the numbers together, and all the variables

3b-(-(3b+1)+7(b-1))=0



We calculate terms in parentheses: -(-(3b+1)+7(b-1)), so:

-(3b+1)+7(b-1)

We multiply parentheses

-(3b+1)+7b-7

We get rid of parentheses

-3b+7b-1-7

We add all the numbers together, and all the variables

4b-8

Back to the equation:

-(4b-8)



We get rid of parentheses

3b-4b+8=0

We add all the numbers together, and all the variables

-1b+8=0

We move all terms containing b to the left, all other terms to the right

-b=-8

b=-8/-1

b=+8

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