6(2x+3)=4(2x+1)+15

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Solution for 6(2x+3)=4(2x+1)+15 equation:



6(2x+3)=4(2x+1)+15
We move all terms to the left:
6(2x+3)-(4(2x+1)+15)=0
We multiply parentheses
12x-(4(2x+1)+15)+18=0
We calculate terms in parentheses: -(4(2x+1)+15), so:
4(2x+1)+15
We multiply parentheses
8x+4+15
We add all the numbers together, and all the variables
8x+19
Back to the equation:
-(8x+19)
We get rid of parentheses
12x-8x-19+18=0
We add all the numbers together, and all the variables
4x-1=0
We move all terms containing x to the left, all other terms to the right
4x=1
x=1/4
x=1/4

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