10-2(x+3)=x+19

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Solution for 10-2(x+3)=x+19 equation: 



10-2(x+3)=x+19

We move all terms to the left:

10-2(x+3)-(x+19)=0

We multiply parentheses

-2x-(x+19)-6+10=0

We get rid of parentheses

-2x-x-19-6+10=0

We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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