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6(2x+3)=-2(-x+1)
We move all terms to the left:
6(2x+3)-(-2(-x+1))=0
We add all the numbers together, and all the variables
6(2x+3)-(-2(-1x+1))=0
We multiply parentheses
12x-(-2(-1x+1))+18=0
We calculate terms in parentheses: -(-2(-1x+1)), so:We get rid of parentheses
-2(-1x+1)
We multiply parentheses
2x-2
Back to the equation:
-(2x-2)
12x-2x+2+18=0
We add all the numbers together, and all the variables
10x+20=0
We move all terms containing x to the left, all other terms to the right
10x=-20
x=-20/10
x=-2
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