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g+1/2g=352
We move all terms to the left:
g+1/2g-(352)=0
Domain of the equation: 2g!=0We multiply all the terms by the denominator
g!=0/2
g!=0
g∈R
g*2g-352*2g+1=0
Wy multiply elements
2g^2-704g+1=0
a = 2; b = -704; c = +1;
Δ = b2-4ac
Δ = -7042-4·2·1
Δ = 495608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{495608}=\sqrt{4*123902}=\sqrt{4}*\sqrt{123902}=2\sqrt{123902}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-704)-2\sqrt{123902}}{2*2}=\frac{704-2\sqrt{123902}}{4} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-704)+2\sqrt{123902}}{2*2}=\frac{704+2\sqrt{123902}}{4} $
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