6(2x+1)=7(3x-2)

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Solution for 6(2x+1)=7(3x-2) equation: 



6(2x+1)=7(3x-2)

We move all terms to the left:

6(2x+1)-(7(3x-2))=0

We multiply parentheses

12x-(7(3x-2))+6=0



We calculate terms in parentheses: -(7(3x-2)), so:

7(3x-2)

We multiply parentheses

21x-14

Back to the equation:

-(21x-14)



We get rid of parentheses

12x-21x+14+6=0

We add all the numbers together, and all the variables

-9x+20=0

We move all terms containing x to the left, all other terms to the right

-9x=-20

x=-20/-9

x=2+2/9

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