6(2x+1)=3(x-3)+7

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Solution for 6(2x+1)=3(x-3)+7 equation:



6(2x+1)=3(x-3)+7
We move all terms to the left:
6(2x+1)-(3(x-3)+7)=0
We multiply parentheses
12x-(3(x-3)+7)+6=0
We calculate terms in parentheses: -(3(x-3)+7), so:
3(x-3)+7
We multiply parentheses
3x-9+7
We add all the numbers together, and all the variables
3x-2
Back to the equation:
-(3x-2)
We get rid of parentheses
12x-3x+2+6=0
We add all the numbers together, and all the variables
9x+8=0
We move all terms containing x to the left, all other terms to the right
9x=-8
x=-8/9
x=-8/9

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