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6(2x+1)-4=10x+2+2x
We move all terms to the left:
6(2x+1)-4-(10x+2+2x)=0
We add all the numbers together, and all the variables
6(2x+1)-(12x+2)-4=0
We multiply parentheses
12x-(12x+2)+6-4=0
We get rid of parentheses
12x-12x-2+6-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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