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2x+4(x-1)=3(-x+2)
We move all terms to the left:
2x+4(x-1)-(3(-x+2))=0
We add all the numbers together, and all the variables
2x+4(x-1)-(3(-1x+2))=0
We multiply parentheses
2x+4x-(3(-1x+2))-4=0
We calculate terms in parentheses: -(3(-1x+2)), so:We add all the numbers together, and all the variables
3(-1x+2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
6x-(-3x+6)-4=0
We get rid of parentheses
6x+3x-6-4=0
We add all the numbers together, and all the variables
9x-10=0
We move all terms containing x to the left, all other terms to the right
9x=10
x=10/9
x=1+1/9
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