6(2w-4)=3(w+1)+9(w-3)

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Solution for 6(2w-4)=3(w+1)+9(w-3) equation: 



6(2w-4)=3(w+1)+9(w-3)

We move all terms to the left:

6(2w-4)-(3(w+1)+9(w-3))=0

We multiply parentheses

12w-(3(w+1)+9(w-3))-24=0



We calculate terms in parentheses: -(3(w+1)+9(w-3)), so:

3(w+1)+9(w-3)

We multiply parentheses

3w+9w+3-27

We add all the numbers together, and all the variables

12w-24

Back to the equation:

-(12w-24)



We get rid of parentheses

12w-12w+24-24=0

We add all the numbers together, and all the variables

=0

w=0/1

w=0

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