6(2t-1)-5(t+1)=0

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Solution for 6(2t-1)-5(t+1)=0 equation: 



6(2t-1)-5(t+1)=0

We multiply parentheses

12t-5t-6-5=0

We add all the numbers together, and all the variables

7t-11=0

We move all terms containing t to the left, all other terms to the right

7t=11

t=11/7

t=1+4/7

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