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2(3x-4)=2(x+4)
We move all terms to the left:
2(3x-4)-(2(x+4))=0
We multiply parentheses
6x-(2(x+4))-8=0
We calculate terms in parentheses: -(2(x+4)), so:We get rid of parentheses
2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
6x-2x-8-8=0
We add all the numbers together, and all the variables
4x-16=0
We move all terms containing x to the left, all other terms to the right
4x=16
x=16/4
x=4
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