6(2t+1)-11=t-(t+4)

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Solution for 6(2t+1)-11=t-(t+4) equation: 



6(2t+1)-11=t-(t+4)

We move all terms to the left:

6(2t+1)-11-(t-(t+4))=0

We multiply parentheses

12t-(t-(t+4))+6-11=0



We calculate terms in parentheses: -(t-(t+4)), so:

t-(t+4)

We get rid of parentheses

t-t-4

We add all the numbers together, and all the variables

-4

Back to the equation:

-(-4)



We add all the numbers together, and all the variables

12t-1=0

We move all terms containing t to the left, all other terms to the right

12t=1

t=1/12

t=1/12

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