-4(4y-3)+8y=5+2(2y-4)

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Solution for -4(4y-3)+8y=5+2(2y-4) equation: 



-4(4y-3)+8y=5+2(2y-4)

We move all terms to the left:

-4(4y-3)+8y-(5+2(2y-4))=0

We add all the numbers together, and all the variables

8y-4(4y-3)-(5+2(2y-4))=0

We multiply parentheses

8y-16y-(5+2(2y-4))+12=0



We calculate terms in parentheses: -(5+2(2y-4)), so:

5+2(2y-4)

determiningTheFunctionDomain
2(2y-4)+5

We multiply parentheses

4y-8+5

We add all the numbers together, and all the variables

4y-3

Back to the equation:

-(4y-3)



We add all the numbers together, and all the variables

-8y-(4y-3)+12=0

We get rid of parentheses

-8y-4y+3+12=0

We add all the numbers together, and all the variables

-12y+15=0

We move all terms containing y to the left, all other terms to the right

-12y=-15

y=-15/-12

y=1+1/4

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