6(2r+8)=10(r+3)

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Solution for 6(2r+8)=10(r+3) equation: 



6(2r+8)=10(r+3)

We move all terms to the left:

6(2r+8)-(10(r+3))=0

We multiply parentheses

12r-(10(r+3))+48=0



We calculate terms in parentheses: -(10(r+3)), so:

10(r+3)

We multiply parentheses

10r+30

Back to the equation:

-(10r+30)



We get rid of parentheses

12r-10r-30+48=0

We add all the numbers together, and all the variables

2r+18=0

We move all terms containing r to the left, all other terms to the right

2r=-18

r=-18/2

r=-9

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