F(2)=5(x-3)+17

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Solution for F(2)=5(x-3)+17 equation: 



(2)=5(F-3)+17

We move all terms to the left:

(2)-(5(F-3)+17)=0



We calculate terms in parentheses: -(5(F-3)+17), so:

5(F-3)+17

We multiply parentheses

5F-15+17

We add all the numbers together, and all the variables

5F+2

Back to the equation:

-(5F+2)



We get rid of parentheses

-5F-2+2=0

We add all the numbers together, and all the variables

-5F=0

F=0/-5

F=0

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