6(2n+1)=7(9n+3)+1

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Solution for 6(2n+1)=7(9n+3)+1 equation: 



6(2n+1)=7(9n+3)+1

We move all terms to the left:

6(2n+1)-(7(9n+3)+1)=0

We multiply parentheses

12n-(7(9n+3)+1)+6=0



We calculate terms in parentheses: -(7(9n+3)+1), so:

7(9n+3)+1

We multiply parentheses

63n+21+1

We add all the numbers together, and all the variables

63n+22

Back to the equation:

-(63n+22)



We get rid of parentheses

12n-63n-22+6=0

We add all the numbers together, and all the variables

-51n-16=0

We move all terms containing n to the left, all other terms to the right

-51n=16

n=16/-51

n=-16/51

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