(4+r)=12(40+10r)

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Solution for (4+r)=12(40+10r) equation: 



(4+r)=12(40+10r)

We move all terms to the left:

(4+r)-(12(40+10r))=0

We add all the numbers together, and all the variables

(r+4)-(12(10r+40))=0

We get rid of parentheses

r-(12(10r+40))+4=0



We calculate terms in parentheses: -(12(10r+40)), so:

12(10r+40)

We multiply parentheses

120r+480

Back to the equation:

-(120r+480)



We get rid of parentheses

r-120r-480+4=0

We add all the numbers together, and all the variables

-119r-476=0

We move all terms containing r to the left, all other terms to the right

-119r=476

r=476/-119

r=-4

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