6(2m-1)=2(24-m)

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Solution for 6(2m-1)=2(24-m) equation: 



6(2m-1)=2(24-m)

We move all terms to the left:

6(2m-1)-(2(24-m))=0

We add all the numbers together, and all the variables

6(2m-1)-(2(-1m+24))=0

We multiply parentheses

12m-(2(-1m+24))-6=0



We calculate terms in parentheses: -(2(-1m+24)), so:

2(-1m+24)

We multiply parentheses

-2m+48

Back to the equation:

-(-2m+48)



We get rid of parentheses

12m+2m-48-6=0

We add all the numbers together, and all the variables

14m-54=0

We move all terms containing m to the left, all other terms to the right

14m=54

m=54/14

m=3+6/7

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