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2(x-3)(x+6)=0
We multiply parentheses ..
2(+x^2+6x-3x-18)=0
We multiply parentheses
2x^2+12x-6x-36=0
We add all the numbers together, and all the variables
2x^2+6x-36=0
a = 2; b = 6; c = -36;
Δ = b2-4ac
Δ = 62-4·2·(-36)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*2}=\frac{-24}{4} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*2}=\frac{12}{4} =3 $
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