6(2k-1)=5(k+1)

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Solution for 6(2k-1)=5(k+1) equation: 



6(2k-1)=5(k+1)

We move all terms to the left:

6(2k-1)-(5(k+1))=0

We multiply parentheses

12k-(5(k+1))-6=0



We calculate terms in parentheses: -(5(k+1)), so:

5(k+1)

We multiply parentheses

5k+5

Back to the equation:

-(5k+5)



We get rid of parentheses

12k-5k-5-6=0

We add all the numbers together, and all the variables

7k-11=0

We move all terms containing k to the left, all other terms to the right

7k=11

k=11/7

k=1+4/7

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