(x-7)2=(x+5)(x-1)

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Solution for (x-7)2=(x+5)(x-1) equation: 



(x-7)2=(x+5)(x-1)

We move all terms to the left:

(x-7)2-((x+5)(x-1))=0

We multiply parentheses

2x-((x+5)(x-1))-14=0

We multiply parentheses ..

-((+x^2-1x+5x-5))+2x-14=0



We calculate terms in parentheses: -((+x^2-1x+5x-5)), so:

(+x^2-1x+5x-5)

We get rid of parentheses

x^2-1x+5x-5

We add all the numbers together, and all the variables

x^2+4x-5

Back to the equation:

-(x^2+4x-5)



We add all the numbers together, and all the variables

2x-(x^2+4x-5)-14=0

We get rid of parentheses

-x^2+2x-4x+5-14=0

We add all the numbers together, and all the variables

-1x^2-2x-9=0

a = -1; b = -2; c = -9;
Δ = b2-4ac
Δ = -22-4·(-1)·(-9)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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