6(2c+10)-5c=-6c+8

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Solution for 6(2c+10)-5c=-6c+8 equation: 



6(2c+10)-5c=-6c+8

We move all terms to the left:

6(2c+10)-5c-(-6c+8)=0

We add all the numbers together, and all the variables

-5c+6(2c+10)-(-6c+8)=0

We multiply parentheses

-5c+12c-(-6c+8)+60=0

We get rid of parentheses

-5c+12c+6c-8+60=0

We add all the numbers together, and all the variables

13c+52=0

We move all terms containing c to the left, all other terms to the right

13c=-52

c=-52/13

c=-4

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