6(2b+3)-2b-18=55

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Solution for 6(2b+3)-2b-18=55 equation: 



6(2b+3)-2b-18=55

We move all terms to the left:

6(2b+3)-2b-18-(55)=0

We add all the numbers together, and all the variables

-2b+6(2b+3)-73=0

We multiply parentheses

-2b+12b+18-73=0

We add all the numbers together, and all the variables

10b-55=0

We move all terms containing b to the left, all other terms to the right

10b=55

b=55/10

b=5+1/2

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