4(3y+1)-5y-4=21

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Solution for 4(3y+1)-5y-4=21 equation: 



4(3y+1)-5y-4=21

We move all terms to the left:

4(3y+1)-5y-4-(21)=0

We add all the numbers together, and all the variables

-5y+4(3y+1)-25=0

We multiply parentheses

-5y+12y+4-25=0

We add all the numbers together, and all the variables

7y-21=0

We move all terms containing y to the left, all other terms to the right

7y=21

y=21/7

y=3

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