6(2-n)=3(n-2)

Solution for 6(2-n)=3(n-2) equation:

6(2-n)=3(n-2)

We move all terms to the left:

6(2-n)-(3(n-2))=0

We add all the numbers together, and all the variables

6(-1n+2)-(3(n-2))=0

We multiply parentheses

-6n-(3(n-2))+12=0


We calculate terms in parentheses: -(3(n-2)), so:

3(n-2)

We multiply parentheses

3n-6

Back to the equation:

-(3n-6)


We get rid of parentheses

-6n-3n+6+12=0

We add all the numbers together, and all the variables

-9n+18=0

We move all terms containing n to the left, all other terms to the right

-9n=-18

n=-18/-9

n=+2