6(2-(5+2x))-4x=-20+2(1-8x)

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Solution for 6(2-(5+2x))-4x=-20+2(1-8x) equation: 



6(2-(5+2x))-4x=-20+2(1-8x)

We move all terms to the left:

6(2-(5+2x))-4x-(-20+2(1-8x))=0

We add all the numbers together, and all the variables

6(2-(2x+5))-4x-(-20+2(-8x+1))=0

We add all the numbers together, and all the variables

-4x+6(2-(2x+5))-(-20+2(-8x+1))=0



We calculate terms in parentheses: -(-20+2(-8x+1)), so:

-20+2(-8x+1)

determiningTheFunctionDomain
2(-8x+1)-20

We multiply parentheses

-16x+2-20

We add all the numbers together, and all the variables

-16x-18

Back to the equation:

-(-16x-18)



We get rid of parentheses

-4x+6(2-(2x+5))+16x+18=0

We add all the numbers together, and all the variables

12x+6(2-(2x+5))+18=0

We move all terms containing x to the left, all other terms to the right

12x+6(2-(2x+5))=-18

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