6(2-(3+6x))-4x=-8+2(1-20x)

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Solution for 6(2-(3+6x))-4x=-8+2(1-20x) equation: 



6(2-(3+6x))-4x=-8+2(1-20x)

We move all terms to the left:

6(2-(3+6x))-4x-(-8+2(1-20x))=0

We add all the numbers together, and all the variables

6(2-(6x+3))-4x-(-8+2(-20x+1))=0

We add all the numbers together, and all the variables

-4x+6(2-(6x+3))-(-8+2(-20x+1))=0



We calculate terms in parentheses: -(-8+2(-20x+1)), so:

-8+2(-20x+1)

determiningTheFunctionDomain
2(-20x+1)-8

We multiply parentheses

-40x+2-8

We add all the numbers together, and all the variables

-40x-6

Back to the equation:

-(-40x-6)



We get rid of parentheses

-4x+6(2-(6x+3))+40x+6=0

We add all the numbers together, and all the variables

36x+6(2-(6x+3))+6=0

We move all terms containing x to the left, all other terms to the right

36x+6(2-(6x+3))=-6

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