-(5z-(10z+3))=3+(4z+5)

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Solution for -(5z-(10z+3))=3+(4z+5) equation: 



-(5z-(10z+3))=3+(4z+5)

We move all terms to the left:

-(5z-(10z+3))-(3+(4z+5))=0



We calculate terms in parentheses: -(5z-(10z+3)), so:

5z-(10z+3)

We get rid of parentheses

5z-10z-3

We add all the numbers together, and all the variables

-5z-3

Back to the equation:

-(-5z-3)





We calculate terms in parentheses: -(3+(4z+5)), so:

3+(4z+5)

determiningTheFunctionDomain
(4z+5)+3

We get rid of parentheses

4z+5+3

We add all the numbers together, and all the variables

4z+8

Back to the equation:

-(4z+8)



We get rid of parentheses

5z-4z+3-8=0

We add all the numbers together, and all the variables

z-5=0

We move all terms containing z to the left, all other terms to the right

z=5

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