6(1x+2)+4(1x+2)=40

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Solution for 6(1x+2)+4(1x+2)=40 equation: 



6(1x+2)+4(1x+2)=40

We move all terms to the left:

6(1x+2)+4(1x+2)-(40)=0

We add all the numbers together, and all the variables

6(x+2)+4(x+2)-40=0

We multiply parentheses

6x+4x+12+8-40=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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