2x(3x+5)=6x-33

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Solution for 2x(3x+5)=6x-33 equation: 



2x(3x+5)=6x-33

We move all terms to the left:

2x(3x+5)-(6x-33)=0

We multiply parentheses

6x^2+10x-(6x-33)=0

We get rid of parentheses

6x^2+10x-6x+33=0

We add all the numbers together, and all the variables

6x^2+4x+33=0

a = 6; b = 4; c = +33;
Δ = b2-4ac
Δ = 42-4·6·33
Δ = -776
Delta is less than zero, so there is no solution for the equation

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