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6(12+x)=5(x/3)
We move all terms to the left:
6(12+x)-(5(x/3))=0
We add all the numbers together, and all the variables
6(x+12)-(5(+x/3))=0
We multiply parentheses
6x-(5(+x/3))+72=0
We multiply all the terms by the denominator
6x*3))-(5(+x+72*3))=0
We add all the numbers together, and all the variables
6x*3))-(5(x+216))=0
We add all the numbers together, and all the variables
6x*3))-(5(x=0
Wy multiply elements
18x^2=0
a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{36}=0$
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