4(3y-1)=2(3y+5)

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Solution for 4(3y-1)=2(3y+5) equation: 



4(3y-1)=2(3y+5)

We move all terms to the left:

4(3y-1)-(2(3y+5))=0

We multiply parentheses

12y-(2(3y+5))-4=0



We calculate terms in parentheses: -(2(3y+5)), so:

2(3y+5)

We multiply parentheses

6y+10

Back to the equation:

-(6y+10)



We get rid of parentheses

12y-6y-10-4=0

We add all the numbers together, and all the variables

6y-14=0

We move all terms containing y to the left, all other terms to the right

6y=14

y=14/6

y=2+1/3

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