11x2+-26x-61=0

Solution for 11x2+-26x-61=0 equation:

11x^2+-26x-61=0

We add all the numbers together, and all the variables

11x^2-26x=0

a = 11; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·11·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*11}=\frac{0}{22}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*11}=\frac{52}{22}
=2+4/11
$