6(10+4x)=-3(3x+20)

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Solution for 6(10+4x)=-3(3x+20) equation: 



6(10+4x)=-3(3x+20)

We move all terms to the left:

6(10+4x)-(-3(3x+20))=0

We add all the numbers together, and all the variables

6(4x+10)-(-3(3x+20))=0

We multiply parentheses

24x-(-3(3x+20))+60=0



We calculate terms in parentheses: -(-3(3x+20)), so:

-3(3x+20)

We multiply parentheses

-9x-60

Back to the equation:

-(-9x-60)



We get rid of parentheses

24x+9x+60+60=0

We add all the numbers together, and all the variables

33x+120=0

We move all terms containing x to the left, all other terms to the right

33x=-120

x=-120/33

x=-3+7/11

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