-17(x+2)+6(4x-5)=6(x-5)+14

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Solution for -17(x+2)+6(4x-5)=6(x-5)+14 equation: 



-17(x+2)+6(4x-5)=6(x-5)+14

We move all terms to the left:

-17(x+2)+6(4x-5)-(6(x-5)+14)=0

We multiply parentheses

-17x+24x-(6(x-5)+14)-34-30=0



We calculate terms in parentheses: -(6(x-5)+14), so:

6(x-5)+14

We multiply parentheses

6x-30+14

We add all the numbers together, and all the variables

6x-16

Back to the equation:

-(6x-16)



We add all the numbers together, and all the variables

7x-(6x-16)-64=0

We get rid of parentheses

7x-6x+16-64=0

We add all the numbers together, and all the variables

x-48=0

We move all terms containing x to the left, all other terms to the right

x=48

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