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6(1/6p-5)=6(1/2p+2)
We move all terms to the left:
6(1/6p-5)-(6(1/2p+2))=0
Domain of the equation: 6p-5)!=0
p∈R
Domain of the equation: 2p+2))!=0We multiply parentheses
p∈R
6p-(6(1/2p+2))-30=0
We multiply all the terms by the denominator
6p*2p-30*2p+2))-(6(1+2))=0
We add all the numbers together, and all the variables
6p*2p-30*2p+2))-(63)=0
We add all the numbers together, and all the variables
6p*2p-30*2p=0
Wy multiply elements
12p^2-60p=0
a = 12; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·12·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*12}=\frac{0}{24} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*12}=\frac{120}{24} =5 $
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