20=2(3+c)

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Solution for 20=2(3+c) equation: 



20=2(3+c)

We move all terms to the left:

20-(2(3+c))=0

We add all the numbers together, and all the variables

-(2(c+3))+20=0



We calculate terms in parentheses: -(2(c+3)), so:

2(c+3)

We multiply parentheses

2c+6

Back to the equation:

-(2c+6)



We get rid of parentheses

-2c-6+20=0

We add all the numbers together, and all the variables

-2c+14=0

We move all terms containing c to the left, all other terms to the right

-2c=-14

c=-14/-2

c=+7

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