6(1-7n)+4=10+9(n-5)

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Solution for 6(1-7n)+4=10+9(n-5) equation: 



6(1-7n)+4=10+9(n-5)

We move all terms to the left:

6(1-7n)+4-(10+9(n-5))=0

We add all the numbers together, and all the variables

6(-7n+1)-(10+9(n-5))+4=0

We multiply parentheses

-42n-(10+9(n-5))+6+4=0



We calculate terms in parentheses: -(10+9(n-5)), so:

10+9(n-5)

determiningTheFunctionDomain
9(n-5)+10

We multiply parentheses

9n-45+10

We add all the numbers together, and all the variables

9n-35

Back to the equation:

-(9n-35)



We add all the numbers together, and all the variables

-42n-(9n-35)+10=0

We get rid of parentheses

-42n-9n+35+10=0

We add all the numbers together, and all the variables

-51n+45=0

We move all terms containing n to the left, all other terms to the right

-51n=-45

n=-45/-51

n=15/17

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