6+4x+7x=3(6x-12)

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Solution for 6+4x+7x=3(6x-12) equation: 



6+4x+7x=3(6x-12)

We move all terms to the left:

6+4x+7x-(3(6x-12))=0

We add all the numbers together, and all the variables

11x-(3(6x-12))+6=0



We calculate terms in parentheses: -(3(6x-12)), so:

3(6x-12)

We multiply parentheses

18x-36

Back to the equation:

-(18x-36)



We get rid of parentheses

11x-18x+36+6=0

We add all the numbers together, and all the variables

-7x+42=0

We move all terms containing x to the left, all other terms to the right

-7x=-42

x=-42/-7

x=+6

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